Question: Consider the following program segment.a [ i ] leftarrow 0 for } i leftarrow 0 mathrm { to } n - 1

Consider the following program segment.a[i]\leftarrow0
for }i\leftarrow0\mathrm{ to }n-1\mathrm{ do
(1) What is the input size of this algorithm?
Answer. The input size is n.
(2) Which one is the basic operation?
Answer. The basic operation is the addition in
the statement a[i]larra[j]+i+j at line 5.
(3) Use Detailed Analysis to find the efficiency of the
algorithm.
Answer. Detailed Analysis gives
t(n)=i=0n-11+i=0n-1j=0n-11=n+i=0n-1n
=n+nn=n(n+1)in(n2)
(4) Use Quick Analysis to find the efficiency of the
algorithm.
Answer. Quick analysis on the basic operation
gives
t(n)=i=0n-1j=0n-11=i=0n-1n=nn=n2in(n2)
Note: explain each question and answer, and give any better methods to solve you have and thank you.
 Consider the following program segment.a[i]\leftarrow0 for }i\leftarrow0\mathrm{ to }n-1\mathrm{ do (1)

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