Question: Consider the following recursive implementation of a function to compute Fibonacci numbers: int f ( int n ) { if ( n < = 1

Consider the following recursive implementation of a function to compute Fibonacci numbers:
int f(int n){
if (n <=1){
return n;
} else {
return f(n -1)+ f(n -2);
}
}
What is the largest number of activation records for f that are simultaneously on the stack during the evaluation of a call to f(4)?(Include the record for the original call to f(4) itself.)

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