Question: Consider the following recursive method: function foo ( a: int, b: int ) = > int: if b = = 0 : return 1 else:

Consider the following recursive method:
function foo(a: int, b: int)=> int:
if b ==0:
return 1
else:
x = foo(a, floor(b/3))// Use integer division
y=2* x
if b %2==1:
y=y+a
return y
If you invoke the above method with foo (4,12) what is the sequence of return values in the order they are generated?
Consider the following recursive method: function

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