Consider the following sample data with mean and standard deviation of 16.0 and 6.8, respectively. (You may find it useful to reference the appropriate table: chi-square table or F table)

Class		Frequency
Less than 10			35
10 up to 20			87
20 up to 30			66
30 or more			22
		n = 210

a. Using the goodness-of-fit test for normality, specify the competing hypotheses in order to determine whether or not the data are normally distributed.

• H₀: The data are normally distributed with a mean of 16.0 and a standard deviation of 6.8.; H_A: The data are not normally distributed with a mean of 16.0 and a standard deviation of 6.8.

• H₀: The data are not normally distributed with a mean of 16.0 and a standard deviation of 6.8.; H_A: The data are normally distributed with a mean of 16.0 and a standard deviation of 6.8.

b-1. Calculate the value of the test statistic. (Round the z value to 2 decimal places, all other intermediate values to at least 4 decimal places and final answer to 3 decimal places.)

b-2. Find the p-value.

• p-value < 0.01

• p-value 0.10
• 0.05 p-value < 0.10
• 0.025 p-value < 0.05
• 0.01 p-value < 0.025

c. At the 1% significance level, what is the conclusion?

• Reject H₀; there is enough evidence to support the claim that the data are not normally distributed.

• Do not reject H₀; there is enough evidence to support the claim that the data are not normally distributed.

• Do not reject H₀; there is not enough evidence to support the claim that the data are not normally distributed.

• Reject H₀; there is not enough evidence to support the claim that the data are not normally distributed.