Question: Consider the following single queueing system. Interarrival time for customers and the processing times are distributed as follow: Time between arrivals (minutes) Probability 30 0.23
Consider the following single queueing system. Interarrival time for customers and the processing times are distributed as follow:
| Time between arrivals (minutes) | Probability |
| 30 | 0.23 |
| 60 | 0.37 |
| 90 | 0.28 |
| 120 | 0.12 |
| Service Time (minutes) | Probability |
| 15 | 0.35 |
| 30 | 0.30 |
| 45 | 0.25 |
| 60 | 0.10 |
Perform a simulation for 8 new customers. Use the following set of random numbers for the interarrivals [0.0708, 0.3887, 0.9862, 0.5473, 0.8055, 0.8043, 0.6612], Use the following random numbers for the service time [0.6599, 0.9499, 0.1072, 0.8887, 0.7113, 0.9237, 0. 1178, 0.4023].
Assume that, when the simulation begins there is one customer being serviced (scheduled to be completed in 25 minutes) and there is one customer with 50-minutes service time in the queue.
What was the probability of a customer that waited?
What was the average waiting time for customers who waited?
What was the probability that the server was idle?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
