Consider the following steady, two$-$dimensional velocity field:

vec$(V)(u,v)=(0\mathrm{.}410+2\mathrm{.}1x)vec(i)+(-3\mathrm{.}100-2\mathrm{.}1y)vec(j)$

Calculate the location of the stagnation point. $($Round the final answers to three decimal places. Include a minus sign if necessary.$)$

The location of the stagnation points are $x=$ and $y=.$