Consider the following structures. Using the Roman numeral label, give: CH3 I H-C-OH CH3 I CH3...

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Consider the following structures. Using the Roman numeral label, give: CH3 I H-C-OH CH3 I CH3 I CH3 I H-C-OH H-C-OH HO-C-H I | HO-C-H HO-C-H 1 | H-C-OH HO-C-H T I CH3 CH3 I H-C-OH I H-C-OH I CH3 I II T a. one pair of enantiomers: b. one pair of identical compounds: III I HO-C-H 1 H-C-OH T CH3 IV CH3 I H-C-OH I H-C-OH I HO-C-H I CH3 V (2 pts) (2 pts) Consider the following structures. Using the Roman numeral label, give: CH3 I H-C-OH CH3 I CH3 I CH3 I H-C-OH H-C-OH HO-C-H I | HO-C-H HO-C-H 1 | H-C-OH HO-C-H T I CH3 CH3 I H-C-OH I H-C-OH I CH3 I II T a. one pair of enantiomers: b. one pair of identical compounds: III I HO-C-H 1 H-C-OH T CH3 IV CH3 I H-C-OH I H-C-OH I HO-C-H I CH3 V (2 pts) (2 pts)

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5 H H H HO b OH H CH3 T CHS CH HO HO 11 OH a CH 3 CH 3 Hence OH H 1OH 110 180 relation one pair CH... View the full answer