Question: Consider the following x 8 6 assembly code. . data wordArray WORD 4 DUP ( ? ) , 1 , 2 , 3 , 4
Consider the following x86 assembly code. .data wordArray dwordArray code 8,16 mov eax, SIZEOF wordArray mov ebx, LENGTHOF dwordArray What is the content of EAX and EBX registers respectively? 16,8 WORD 4 DUP (?), 1,2,3,4 DWORD 1,2,3,4,5,6,7,8 4,32 8,8
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To calculate the contents of the EAX and EBX registers we need to understand what the SIZEOF and LEN... View full answer
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