Consider the function ()=228. We want to find its degree two Taylor polynomial 2() at =0 . First, we calculate () . We get: ()= 4xe^x^16 Your last answer was interpreted as follows: 4xe16 The variables found in your answer were: [,xe] Then, we calculate () . We get: ()= 4xe^x^8*(1+8x^16) Your last answer was interpreted as follows: 4xe8(1+816) The variables found in your answer were: [,xe] Putting this together, we can construct the degree two Taylor polynomial 2() at =0 . We obtain: 2()=