Question: Consider the function ( ) = cos 1 2 3 1 2 . f ( x ) = 1 2 cosx 3 1 t 2

Consider the function
()=cos12312.f(x)=12cosx31t2dt.
We want to find its degree two Taylor polynomial 2()T2(x) near =4x=4.
First, we calculate ()f(x). We get:
()=

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