Question: Consider the function f ( x) = ex +2*+ 2cos x- 10 Use Newton's method with an initial value of X1 = 2 to approximate

Consider the function f ( x) = ex +2*+ 2cos x- 10
Consider the function f ( x) = ex +2*+ 2cos x- 10 Use Newton's method with an initial value of X1 = 2 to approximate the root of the function at the n = 4 iteration. What would be the latest value of the absolute approximate error at the n = 4 iteration rounded off to six decimal places? 0.315832 O 0.000165 O 0.004140 0.077655

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