Consider the function $f(x)=\frac{x^{6}7}{x^{\frac{4}{3}}}.$ Complete parts $($a$)$ through $($c$)$ below.

$($a$)$ Find the derivative using the quotient rule. Let $u(x)=x^{6}7$ and $v(x)=x^{\frac{4}{3}}.$How is the derivative of a quotient of two functions defined?

A$.r^{\text{'}}(x)=\frac{v^{\text{'}}(x)*u(x)-u^{\text{'}}(x)*v(x)}{[v(x){]}^2}$

B$.f^{\text{'}}(x)=\frac{v(x)*u^{\text{'}}(x)-u(x)*v^{\text{'}}(x)}{|v(x){|}^2}$

c$.f^{\text{'}}(x)=\frac{v^{\text{'}}(x)*u^{\text{'}}(x)-u(x)*v(x)}{[v(x){]}^2}$

D$.f^{\text{'}}(x)=\frac{v(x)*u(x)-u^{\text{'}}(x)*v^{\text{'}}(x)}{[v(x){]}^2}$