Consider the function f(x) = - 1 Does the function f(x) have a vertical asymptote at r = -3? Justify your answer without using a graphing calculator. (x + 3)3 Of(x) does have a vertical asymptote at r = -3 because lim f(r) = co and lim f(x) = -00. of(x) does not have a vertical asymptote at r = -3 because lim f(r) is a finite number. Of(x) does have a vertical asymptote at z = -3 because lim f(I) = 00. Of(x) does have a vertical asymptote at r = -3 because lim f(r) = co and lim f(x) = -00. of(x) does have a vertical asymptote at c = -3 because lim f(I) = -00