Question: Consider the functions f ( x ) = x 3 - 6 x 2 + 9 x , and , g ( x ) =

Consider the functions
f(x)=x3-6x2+9x, and ,g(x)=x
graphed below.
a. Set up the integrals for the area between f and g from 0tob(thisis the green- and yellow-shaded
regions).
Note: You will need to find the x-values, a and b.
Area =0|,?o++
b. Set upan integral for the volume of the solid obtained by rotating the green-shaded region (the first
region) about the line y=-6.
Volume =0
c. Set upan integral for the volume of the solid obtained by rotating the yellow-shaded region (the
second region) about the line x=5.
Volume =b. Set upan integral tor the volume of the solid obtained by rotating the green-shaded region (the first region) about the line y=-6.
Volumeb=ar(0)
c. Set upan integral for the volume of the solid obtained by rotating the yellow-shaded region (the second region) about the line x=5.
Volumeb=ar(l),?
d. Set upan integral for the arc length off(x) from x=0tox=a.
Note: This is the same f(x) and a from the nrevious three narts.
Arc Length =0
?
e. Finally, set upan integral for the surface area of the solid obtained by rotating the shaded region in part d from x=0tox=a about the x-axis.
Surface Area =0
?
Consider the functions f ( x ) = x 3 - 6 x 2 + 9

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