Consider the indefinite integral ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{6x^3+5x^2-147x-130}{x^2-25}dx$

Then the integrand decomposes into the form

$ax+b+\frac{c}{x-5}+\frac{d}{x+5}$

where

$a=$

$b=$

$c=$

$d=$

Integrating term $by$ term, $we$ obtain that

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{6x^3+5x^2-147x-130}{x^2-25}dx=$