Question: Consider the initial value problem y ' - 1 5 2 y = 6 t + 7 e t , y ( 0 ) =

Consider the initial value problem y'-152y=6t+7et,y(0)=y0.
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Find the value of y0 that separates solutions that grow positively as t from those that grow negatively. How does the solution that corresponds to this critical value of y0 behave as t?
y0=
As t, the solution that corresponds to this critical value of y0
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Question 9
Consider the initial value problem y ' - 1 5 2 y

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