Consider the irrigation system shown below. The system consists of a reservoir with a maximum depth...

  

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Consider the irrigation system shown below. The system consists of a reservoir with a maximum depth of h=2.5m, 5 sections of piping with a diameter of 5cm, 2 pipe bends (r/d=3), a wide-open globe valve, a pump drawing 500W of electricity with an efficiency of 78%, and a sprinkler. The sprinkler itself consists of a bend (Knozzle bend-0.3), and 60° contraction and an infinite expansion. The angle 8 of the sprinkler nozzle with respect to the horizontal is adjustable. More details are shown in the schematic later. 2. Tasks: 1. Calculate the maximum distance the water jet from the sprinkler will reach for a reservoir depth of h=2.5m and a nozzle diameter of 3cm. Assume Schematic ● ● ● ● 2.5m ● Evaluate the change in: a. distance the jet will reach; b. volume flow rate; C. nozzle velocity; and d. pump head as a functions of: I. II. III. reservoir angle (5º ≤ 0 ≤ 85°, steps of 5°). nozzle diameter (0.5cm D ≤ 5cm, steps of 0.5cm). Water level is in the reservoir (0.25m ≤h ≤ 2.5m, steps of 0.25m). 1.5m d=5cm r/D=3 1.5m 16.2m Globe valve (wide open) Steel 3.8m Pump: 2000W ● r/D=3 0.15m 25.9m Knozzle_bend=0.3 60° contraction Infinite expansion J+0.1 $0.15m The reservoir is open to atmosphere. The location (y = 0.15m) of the nozzle exit is independent of the angle of the nozzle. The kinetic energy correction factor is everywhere a ≈ 1. Use the Swamee and Jain function for approximating friction factor in turbulent pipes. The water from the sprinkler follows projectile motion. Assume a sharp entrance to and exit from the pipes/nozzles (r/d=0). Water: μ = 0.00114 Pa-s, p = 1000 kg/m³ Consider the irrigation system shown below. The system consists of a reservoir with a maximum depth of h=2.5m, 5 sections of piping with a diameter of 5cm, 2 pipe bends (r/d=3), a wide-open globe valve, a pump drawing 500W of electricity with an efficiency of 78%, and a sprinkler. The sprinkler itself consists of a bend (Knozzle bend-0.3), and 60° contraction and an infinite expansion. The angle 8 of the sprinkler nozzle with respect to the horizontal is adjustable. More details are shown in the schematic later. 2. Tasks: 1. Calculate the maximum distance the water jet from the sprinkler will reach for a reservoir depth of h=2.5m and a nozzle diameter of 3cm. Assume Schematic ● ● ● ● 2.5m ● Evaluate the change in: a. distance the jet will reach; b. volume flow rate; C. nozzle velocity; and d. pump head as a functions of: I. II. III. reservoir angle (5º ≤ 0 ≤ 85°, steps of 5°). nozzle diameter (0.5cm D ≤ 5cm, steps of 0.5cm). Water level is in the reservoir (0.25m ≤h ≤ 2.5m, steps of 0.25m). 1.5m d=5cm r/D=3 1.5m 16.2m Globe valve (wide open) Steel 3.8m Pump: 2000W ● r/D=3 0.15m 25.9m Knozzle_bend=0.3 60° contraction Infinite expansion J+0.1 $0.15m The reservoir is open to atmosphere. The location (y = 0.15m) of the nozzle exit is independent of the angle of the nozzle. The kinetic energy correction factor is everywhere a ≈ 1. Use the Swamee and Jain function for approximating friction factor in turbulent pipes. The water from the sprinkler follows projectile motion. Assume a sharp entrance to and exit from the pipes/nozzles (r/d=0). Water: μ = 0.00114 Pa-s, p = 1000 kg/m³

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