Consider the language L3=L1L2 Give the PDA M3= (K3, , 3, 3, s3, F3) that accepts

Consider the language L3=L1∩L2 Give the PDA M3= (K3, ∑ , Г3, Δ3, s3, F3) that accepts L3 using the construction algorithm based on the intersection of a PDA and a DFA.

Where L1= {w in ∑*: w contains the same number of a's and b's} PDA and L2=a*b* DFA.

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Every regular language is also a CFL So PDA can be used t... View the full answer