Question: Consider the linear program: Maximize 2x2 - 5x3 Subject to + X3 X4 2x1 + x2 + 6x3 + Xs = 6 X! . x2

Consider the linear program: Maximize 2x2 - 5x3

Consider the linear program: Maximize 2x2 - 5x3 Subject to + X3 X4 2x1 + x2 + 6x3 + Xs = 6 X! . x2 + 3x3 X120 for i = 1...5 001] Suppose you are told that a feasible basis is B = [x2 X3 X = 1 1 2 (-101 a) Compute the basic feasible solution XP = (x3, X5, X)" corresponding to this basis. b) Compute the simplex tableau corresponding to this basis. c) Identify an entering variable and an exiting variable (if there are any) and compute the new tableau by pivoting. d) What is the new basis corresponding to your new tableau? e) Is the new solution optimal? Why

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