Consider the same liquid phase irreversible reaction as described in Problem $1.$ Here, the reaction is to occur in two identical CSTRs as shown $($with $V_1=V_2=20L).$ The process remains isothermal.

Component A is supplied by Stream $1,$ with $Q_1=2\frac{L}{s}$ and $C_{A1}=1mo\frac{l}{L}.$ Component B is supplied by Stream $2,$ with $Q_2=2\frac{L}{s}$ and $C_{B2}=1mo\frac{l}{L}.$

Stream $2$ is split into Streams $3$ and $4$ as shown; the partitioning is measured by the parameter

$x-=\frac{Q_3}{Q_2}$

The overall conversion of $A$ is

$x_A=1-\frac{F_{A6}}{F_{A1}}$

$($a$)$ Plot $x_A$ vs $x,$ with the $x_A-$axis ranging from $0\mathrm{.}6$ to $0\mathrm{.}9,$ and the $x-$axis from $0$ to $1.$

$($b$)$ What is the configuration that gives the highest conversion, and what is that highest value of $x_A?$