Considering a multicycle divider, divide $13$ by $5,$ indicating the values $$of the registers listed in the questions at the end of each clock cycle indicated. Consider that the inputs and results are represented with $4$ bits, and that at the end of cycle $0($initialization$)$:

Quotient, Cycle $1$

Remainder, Cycle $1$

Divider, Cycle $1$

Quotient, Cycle $2$

Remainder, Cycle $2$

Divider, Cycle $2$

Quotient, Cycle $3$

Remainder, Cycle $3$

Divider, Cycle $3$

Quotient, Cycle $4$

Remainder, Cycle $4$

Divider, Cycle $4$

Quotient, Cycle $5$

Remainder, Cycle $5$

Divider, Cycle $5$