Question: Considering the following MIPS code: begin: loop: finish: addi $t 0 , $zero, 2 2 move $t 1 , $zero li $a 0 , 0

Considering the following MIPS code: begin:
loop:
finish:
addi $t0, $zero, 22 move $t1, $zero
li $a0,0
beq $t0, $t1, finish add $t1, $t1, $a0 addi $t0, $t0,-4 addi $a0, $a0,1
j loop

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