Question: Construct dfa to accept: L = {w | w {a,b}* where w contains abba} L = {w | w contains at most 3 a's and

Construct dfa to accept:

L = {w | w Construct dfa to accept: L = {w | w {a,b}* where w {a,b}* where w contains "abba"}

L = {w | w contains at most 3 a's and ends in b} (assume contains "abba"} L = {w | w contains at most 3 a's = {a,b})

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