Continue with the previous MILP, we can solve the LP relaxation of the above MILP and find the optimal solution for LP relaxation is $($x$1=3\mathrm{.}14$ and x$2=2\mathrm{.}60)$ with objective value of $14\mathrm{.}08.$ Rounding x$1$ down to $3,$ we can find a new solution $($x$1=3$ and x$2=2\mathrm{.}60).$ It is clear that this new solution is a feasible solution to MILP. Is it true that this new feasible solution $($x$1=3$ and x$2=2\mathrm{.}60)$ is also the optimal solution to the original MILP?

Question $2$ options:

True

False