Question: Continuity Equation 4 , Part 1 A p - type semiconductor with = 1 0 1 3 3 NA = 1 0 1 3 cm

Continuity Equation 4, Part 1
A p-type semiconductor with =10133NA=1013cm3 occupies a half-space, 0x0, with an interface at =0x=0. The interface has a contact with another semiconductor which keeps the minority carrier concentration zero at all times, (=0)=0n(x=0)=0. Inside the semiconductor, there is no electric field and the minority carrier lifetime is =1010n=1010s.
Find the expression for steady-state excess minority carrier concentration as a function of x,()n(x), in the semiconductor 0x0. Write your expression in terms of equilibrium minority carrier concentration 0n0, diffusion length L, generation rate G, minority carrier lifetime (tau), diffusion coefficient D and mobility (mu). Your equation does not have to contain all of these variables.

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