Conversion between Binary, Octal and Hexadecimal Systems:

Since $8=2^3$ and $16=2^4,$ each octal digit corresponds to three binary digits and each hexadecimal digit corresponds to four binary digits.

The conversion from binary to octal $/$ hexadecimal is easily done by grouping the binary number into groups of three $/$ four bits each, starting from the binary point.

Ex: $,(10110001101011\mathrm{.}111100000110{)}_2=(?{)}_8$

Ex: $,(10110001101011\mathrm{.}111100000110{)}_2=(?{)}_{16}$