Question: Convert the following C code snippet to x86 assembly. While ( c > 0 ) { if ( a == b ) { b =

Convert the following C code snippet to x86 assembly.

While ( c > 0 ) {

if ( a == b ) {

b = 5 * b;

}

else if ( a > b ) {

a = a - b;

}

c--;

}

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