Question: Convert the following code to ARM Assembly Language code typedef struct node { int val; struct node * next; } node_t; int main(){ node_t *
Convert the following code to ARM Assembly Language code
typedef struct node { int val; struct node * next; } node_t; int main(){
node_t * head = NULL; head = malloc(sizeof(node_t)); if (head == NULL) { return 1; } head->val = 1; head->next = NULL; }
list* insert(linked* list, val){
node_t * head = NULL; head = malloc(sizeof(node_t)); head->val = 1; head->next = malloc(sizeof(node_t)); head->next->val = 2; head->next->next = NULL;
}
void print_list(node_t * head) { node_t * current = head; while (current != NULL) { printf("%d ", current->val); current = current->next; } } Step by Step Solution
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