Question: Convert the NFA defined by (q0, a) = {q0, q1}. (q1, b) = {q1, q2} (q2, a) = {q2} (q0, ) = {q1, q2} with

Convert the NFA defined by (q0, a) = {q0, q1}. (q1, b) = {q1, q2} (q2, a) = {q2} (q0, ) = {q1, q2} with initial state q0 and final state q2 into an equivalent DFA. Assume the input alphabets are {a, b}

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