Converting a Decimal to Hexadecimal Using MIPS Assembly Language

Step $1$: Generate a look$-$up table in the data segment.

$($hint: hexLookup: $.$byte $\text{'}0\text{'},\text{'}1\text{'},\text{'}2\text{'},\text{'}3\text{'},\text{'}4\text{'},\text{'}5\text{'},\text{'}6\text{'},\text{'}7\text{'},\text{'}8\text{'},\text{'}9\text{'},\text{'}$A$\text{'},\text{'}$B$\text{'},\text{'}$C$\text{'},\text{'}$D$\text{'},\text{'}$E$\text{'},\text{'}$F$\text{'})$

Step $2$: Input an integer range from $0$ to $15$ and save it in the $t$0.$

Step $3$: Output the hexadecimal representation of the integer

$($hint: load the address of the table with: la $t$1,$ hexLookup

Get the offset based on the integer and saved the offset in $t$2$

Load the byte from the memory to t$3$ with: lb $t$3,0($$t$2),$ then print it$.)$