Copy by reference versus shallow copy

Consider this code:

import copy

class ThreeNumbers:

def init $\_($self$,$ n$1$: float, n$2$: float, n$3$: float$)$:

self.number$1=$ n$1$

self.number$2=$ n$2$

self.number$3=$ n$3$

def main$()$

object$1=$ ThreeNumbers$(2,3\mathrm{.}14159,2\mathrm{.}71828)$

object$2=$ object$1$

object$3=$ copy.copy$($object$1)$

object$1.$number$1=9$

object$2.$number$1=47$

print$($object$1)$

print$($object$2)$

print$($object$3)$

print$($object$1.$number$1,$ object$2.$number$1,$ object$3.$number$1)$

if $\_$name$\_=="\_\_$main$\_\_"$:

main$()$

Draw Complete Diagram $/$ Call Stack

T$/$F Line $12$ copies a reference $($memory address$)$

b$.$ T$/$F Line $13$ performs a deep copy

c$.$ T$/$F Lines $16-18$ output a memory address since $\_\_$str$\_\_$ was not implemented in the class ThreeNumbers.

d$.$ What does line $19$ output? e$.$ Draw the memory diagram