Correct answer

Given: Side length of the square plates, L = 26.9 cm = 0.269 m Distance between the plates, d = 2.67 cm = 0.0267 m Dielectric constant of the first dielectric, Ky = 28.1 Dielectric constant of the second dielectric, ko = 5.47 Fraction of the space filled with the first dielectric, i Fraction of the space filled with the second dielectric, : The permittivity of free space, e9 = 8.854 x 10 F/m The area of the plates, A = L x [ = (0.269 m)? = 0.0723 m* |. Capacitance with the first dielectric: enh. 1A x r G= 5 d 2. Capacitance with the second dielectric: C Ego A x F y= d se Equivalent capacitance of the combination (since they are in parallel): Cu = C1 +O Using the given values: 8.854 x 10 ? F/m x 28.1 x 0.0723 m? x 4 'On 5 ~134x10 FR 0.0267 m 8.854 x 10 1? F/m x 5.47 x 0.0723 m? x 2 106 x 10 F a 0.0267 m ~* Cog = 1.34 x 10 F+1.06 x 10 F = 2.40 x10 F Therefore, the equivalent capacitance of this combination is approximately 2.40 x 10 ' F