(coshx + sinhx) = cosh nx + sinh nx Start with cosh u = e u +...

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(coshx + sinhx) = cosh nx + sinh nx

Start with cosh u = e ^u + e- ^u/2 and sinh u = e ^u – e ^-u/2 on both sides.

Related Book For answer-question

Calculus Early Transcendentals

ISBN: 978-0321947345

2nd edition

Authors: William L. Briggs, Lyle Cochran, Bernard Gillett

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Posted Date: Jan 17, 2020 09:19 AM

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(coshx + sinhx) = cosh nx + sinh nx Start with cosh u = e u +...

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prove cosh xsinh xn cosh nx sinh nx as we know ... View the full answer

Calculus Early Transcendentals

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