Could anyone please answer this physics homework for me? I am inserting the lesson and the questions to be answered. Thank you in advance.

Below are the questions to be answered.

CONCAVE MIRROR Case 1 Object is beyond C m- 2 do = 9 cm di= ? 145 ho = 2 cm hit ? between - - di CYF - m m= hil thist Diminished & S she Real Judit All the cases of Object in Conclave Mirror produces inverted image except the object is between f and Miccor. LET'S Do the calculations f do di 3 19 di do 2 m = -di di di = 1 4 . 5 do Im = hi 3 di =1 49. 2 di- 9 i = 4 .5 then image is invertedCase 2: object is between CrF do = 6 cm hy = 2 cm m=? dis ? f = 4 cm hi =? LOST Case 3 object is at F f = 4 cm hi = ? dizim =? ho = 2cm LOST Cause 4 object is at LOST ( = 6 cm # ho= Icm m = ? Case 5 object is between F o Mirror, f= yom ho= zam m = ? do = 2 cm his ? di = ? LOST Due Oct. 16 to be marked as TEST