Question: Could i please get some help with this, it would mean a lot, thank you ! The ray diagram and calculations area. 4 5 6

 Could i please get some help with this, it would meana lot, thank you ! The ray diagram and calculations area. 45 6 7 8 9 10 11 12 13 14 15 1617 18 19 20 21 212 23 24 25 26 wo ww

Could i please get some help with this, it would mean a lot, thank you ! The ray diagram and calculations area.

le I JOHNSON LEVEL & TOOL MFG. CO. INC. OL 19 S4 3 21 8ths Ray Diagram for Part ( 9 ) :Of = 20 0m 1 = 360m 300 mm toomm do =200 mm di = 120 mm *= 360 MM IMAGE 420 mm* = 200 mm OBJECT Af-loommOne lens with focal length, f =

4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 212 23 24 25 26 wo ww le I JOHNSON LEVEL & TOOL MFG. CO. INC. OL 19 S 4 3 21 8ths Ray Diagram for Part ( 9 ) : Of = 20 0m 1 = 360m 300 mm toomm do = 200 mm di = 120 mm *= 360 MM IMAGE 420 mm * = 200 mm OBJECT Af-loommOne lens with focal length, f = 100mm do, mm di, mm ho hi Mh Ma Experiment 0.9357 mm - 0.60 mm 200 mm 120 mm 19 mm 17.78 mm Calculations Ray diagramThe object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) The magnification of the image, M, is M = h, di iveise Ivequi vi lage 1 10 givenvy ure writes vququvI. do (5) f 2 di = do - f2 Equation 5 allows us to find the final image distance value for the two-lens system. The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces the magnification M = - =_1. Similarly, the second lens causes the magnification M' = --1. The totalThe object distance, focal length and image distance for a thin lens are related by thin lens equation. (2) The magnification of the image, M, is M = h, di iveise Ivequi vi lage 1 10 givenvy ure writes vququvI. do (5) f 2 di = do - f2 Equation 5 allows us to find the final image distance value for the two-lens system. The orientation and size of the final image can be found as follows: The total magnification produced by a lens system is equal to the product of the magnifications produced by each lens individually. Using Equation 3, we find that the first lens produces the magnification M = - =_1. Similarly, the second lens causes the magnification M' = --1. The totalII' II magnication of the system, then, is m = MM ', showing that the nal image is inverted ifm0, and Changed in size by a factor of :11 compared with the original object. This value must be in agreement with the results obtained in experiment where the magnication can be found from formulae: M = %, M'r = ?, m = MM' and u.' = hi. 0 0" [Calculated value Experimental value| = - 100% Calculated value

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