Question: Could someone please solve the 5th. OPTION 15 The probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more

Could someone please solve the 5th.

Could someone please solve the 5th. OPTION 15 The probabilities that an

OPTION 15 The probabilities that an automobile mechanic will service 3, 4, 5, 6, 7, or 8 or more cars on any given workday are, respectively, 0.12, 0.19, 0.28, 0.24, 0.10, and 0.07. 0. What is here the random experiment? 1. Describe the sample space: (1 p.) a) by sentence: (1 p.) b) by writing its elements. (1 p.) c) What is the size of sample space? 2. Draw in Venn Diagram the following events: (1 p.) A {mechanic will service at least 3 cars) ; (1 p.) B={mechanic will service at least 3 cars and at most 7 cars); (1 p.) C {mechanic will service at least 8 cars } . 3. Describe by word or by writing its elements: (1 p.) a) Opposite event of A; (1 p.) b) Union of the events A and B: (1 p.) c) Intersection of events A, B and C. H 4. Find the probabilities: (1 p.) a) P(A); (1 p.) b) P(B); (1 p.) c) P(C): (1 p.) d) 3 a): (1 p.) e) 3 b): (1 p. ) f) 3 c). 5. (5 p.) Are the events A, B, C hypothesis? Why? Prove your answer. 6. (5 p.) Came up any random variable and calculate it's numerical characteristics, define functional characteristics

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