Could someone with expertise in C programming help me with the following code? It seems simple, and short, but I'm a bit lost on how to do it. Thank you so much for your help!

Create a program in the C language that does the following:

• Create a loop that loops from 1 to 999, inclusive.
• For each number in the loop, output the equivalent word English
• You will need to separate the number into three digits - the one's, ten's, and hundred's digit.
• To do this, divide by 1, 10, or 100, and take modulo 10 - this will give you a single digit.
  • For example, this variable will store the hundred's digit: int hundreds = (number / 100) % 10;
  • And then, use variable "hundreds" in a switch-case to output the word(s) for one hundred, two hundred, etc.
  • Then, find the ten's digit, then the one's digit.
• Output the number, an equals sign, and then the number in your chosen language.
  • Put a space between the words for hundred's, ten's, and one's place.
• When displaying on the commandline, the numbers 1 to 999 will quickly scroll by too fast and too much to check your output.
• To verify your output, use redirection to store the output into a text file named output.txt.
  • For example, to redirect output to a file: ./program > output.txt
  • This will generate a .txt file containing the print
• Other tips
  • Only 1 loop is needed, that is the loop that counts from 1 to 999.
  • Only 4 variables were needed, all of them integer variables.
  • Whether you are using if-statements or switch-cases, you will have 3 consecutive groups (PLEASE USE SWITCH CASES)
    • Each for the one's, ten's, and hundred's.
  • Order MATTERS! Check the hundreds first, then the tens, then the ones.
  • There is no user input in this program.

Output should look like this: This program counts in English from1 to 999. 1 = one 2 = two 3 = three 999 = nine-hundred ninety nine