Could this be checked - and please explain what or why they are wrong?

win the first column of D is the eigenvalue associated with the eigenvector in the first scolumn of V. The eigenvectors in V are normalized, each having a magnitude of 1. [v, D] = eiglA) Use the following matrix C for this activity. [6 3 -8] = 0 -2 0 [1 0 -3] Script Save C Reset BE MATLAB Documentation 1 Enter the matrix C. 2 C = [6 3 -8; 0 -2 0; 1 0 -3] 3 &Find the coefficients of the characteristic polynomial. Store them in PolyCoeffs. 4 PolyCoeffs = poly(C) Use the command roots() to find the eigenvalues. Store them in evals. 6 evals = roots (PolyCoeffs) 7 Use the eig command. Store the eigenvalues in matrix eigiag. Store the associated Seigenvectors in eigv. 9 [eigniag, eigv] = eiglC) Run Script Assessment: 3 of 5 Tests Passed Submit Matrix C correct Characteristic polynomial coefficients PolyCoeffs correct Eigenvalues evals correct Diagonal matrix of eigenvalues eigniag correct Variable eigiag has an incorrect value. Feedback hidden for errors below, as these errors may be due to the initial error. Hide Feedback Matrix of eigenvectors eigv correct Variable eigv has an incorrect value. Output C -2 PolyCoeffs = -1 -16 -20 evals = 5. 0000 + 0.00001 -2. 0000 + 0.00001 -2. 0000 - 0.00001 eigDiag = 0.9923 0. 7071 0. 7071 0 . 0000 0 . 1240 0. 7071 0. 7071 eigv =