Question: Could you please explain how to read Figure 5.9 and how we got the value of 0.0122cP. Thank you very much! Figure 5.9: Viscosity of

Could you please explain how to read Figure 5.9 and how wegot the value of 0.0122cP. Thank you very much! Figure 5.9: ViscosityCould you please explain how to read Figure 5.9 and how we got the value of 0.0122cP. Thank you very much!

Figure 5.9: Viscosity of natural gases at atmospheric pressure (from CARR et al, 1954) Determination of the gas viscosity at temperature T=90.5C (194.9F,654.7R ) and at pressure p=12.5MPa (1800 psia). The specific gas gravity was found as g=0.7018. From Figure 5.9, the viscosity at atmospheric pressure and operating temperature can be read off as g,1=0.0122cP Figure 5.9: Viscosity of natural gases at atmospheric pressure (from CARR et al, 1954) Determination of the gas viscosity at temperature T=90.5C (194.9F,654.7R ) and at pressure p=12.5MPa (1800 psia). The specific gas gravity was found as g=0.7018. From Figure 5.9, the viscosity at atmospheric pressure and operating temperature can be read off as g,1=0.0122cP

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