Question: CRYPTOGRAPHY Suppose the DES mangler function mapped every 32-bit value to zero, regardless of the value of its input. What function would DES then compute?

CRYPTOGRAPHY

Suppose the DES mangler function mapped every 32-bit value to zero, regardless of the value of its input. What function would DES then compute?

I understand that the initial input would not change due to having 16 rounds. The answers I find on google say that the end result would then just be a permutation that changes the even and odd bits.

Why is that?

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