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In exercising, a weight lifter loses $0\mathrm{.}207$ kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is $1\mathrm{.}78{10}^{5}J.($a$)$ Assuming that the latent heat of vaporization of perspiration is $2\mathrm{.}42{10}^6\frac{J}{k}g,$ find the change in the internal energy of the weight lifter. $($b$)$ Determine the minimum number of nutritional Calories of food that must be consumed to replace the loss of internal energy. $(1$ nutritional Calorie $=4186J).$

$($a$)$ Number

Units

$($b$)$ Number

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