Current Attempt in Progress

When a valve is opened, the velocity of water in a certain pipe is given by $u=3(5-e^{-t}),v=0,$ and $w=0$ where $u$ is in $f\frac{t}{s}$ and $t$ is in seconds. Determine

$($a$)$ the maximum velocity of the water,

$($b$)$ the maximum acceleration of the water.

$($a$)v_{\text{m}\text{a}\text{x}}=f\frac{t}{s}$

$($b$)a_{\text{m}\text{a}\text{x}}=f\frac{t}{s^2}$