Current Attempt in Progress

Your answer is partially correct.

For fully developed laminar pipe flow in a circular pipe, the velocity profile is given by

$u(r)=2(1-\frac{r^2}{R^2})$ in $\frac{m}{s},$ where $R$ is the inner radius of the pipe. Assuming that the pipe diameter is

$4\mathrm{.}6cm,$ find the $($a$)$ maximum and $($b$)$ average velocities in the pipe as well as $($c$)$ the volume flow rate.

$($a$)u(0)=$

$\frac{m}{s}$

$($b$)V=$

$\frac{m}{s}$

$($c$)Q=$

$\frac{m^3}{s}$