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A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative $x$ direction and has a magnitude of $2\mathrm{.}22$ mT $.$ At one instant the velocity of the proton is in the positive $y$ direction and has a magnitude of $2400\frac{m}{s}.$ At that instant, what is the magnitude of the net force acting on the proton if the electric field is $($a$)$ in the positive $z$ direction and has a magnitude of $4\mathrm{.}39\frac{V}{m},($b$)$ in the negative $z$ direction and has a magnitude of $4\mathrm{.}39\frac{V}{m},$ and $($ c $)$ in the positive $x$ direction and has a magnitude of $4\mathrm{.}39\frac{V}{m}?$

$($a$)$ Number

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$($b$)$ Number

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$($c$)$ Number

i

Units