Current Attempt in Progress

Your answer is partially correct

The thin uniform rod in the figure has length $7\mathrm{.}0$ m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle $\backslash (\backslash$theta$=60^\{\backslash$circ$\}\backslash )$ above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position. Assume free$-$fall acceleration to be equal to $\backslash (9\mathrm{.}83\backslash$mathrm$\{$~m$\}/\backslash$mathrm$\{$s$\}^\{2\}\backslash ).$

Number

Units

eTextbook and Media

Hint

GO Tutorial