Your answer is partially correct.

The thin uniform rod in the figure has length $6\mathrm{.}0$ m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle $=30$ above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position. Assume free$-$fall acceleration to be equal to $9\mathrm{.}83\frac{m}{s^2}.$

Number

Units