Current Station Assignment

Demand $($current peak output$)$ is given as $92$ burritos$/$ hour

Task List Current Station

assignment

Station Time

$($sec$/$unit$)$

Time $($in sec; on

average$)$

Design Capacity per

station $($units$/$ hr$)$

Total time$/$Station

time

Utilization

Actual$/$Design

Prepare the base

Station $1$ or Person $136$

$18$

Put the rice $9$ S$1$ S$2$ S$3$ S$4$ S$5$

Add beans $9$

Add protein Station $22121$ Total Task Time

Sour cream and cheese

Station $334$

$22$

Veggies $6$ Cycle Time

Guacamole $6$

Pack Station $42828$ Efficiency

Checkout Station $51010$

Min # of Stations

Load Balancing

a$.$ Given that the first two steps of the process must be setting up the base and adding the rice, and that the last two steps of the process must be packing and then checkout, changes possible are:

$($a$)$ Move beans from s$1$ to s$2,$ and

$($b$)$ Move Guacamole to s$1$ from s$3$

Task List Current Station

assignment

Station Time

$($sec$/$unit$)$

Time $($in sec; on

average$)$

Design Capacity per

station $($units$/$ hr$)$ Utilization

Prepare the base

Station $1$ or Person $1$Put the rice

Guacamole S$1$ S$2$ S$3$ S$4$ S$5$

Add protein Station $2$

Add beans

Sour cream and cheese Station $3$

Veggies Efficiency

Pack Station $4$

Checkout Station $5$

b$.$ Based on Finding Minimum No$.$ of Servers $($stations$)$ balance the problem:

Task List Current Station

assignment

Station Time

$($sec$/$unit$)$

Time $($in sec; on

average$)$

Design Capacity per

station $($units$/$ hr$)$ Utilization

Prepare the base

Station $1$ or Person $1$Put the rice

Guacamole S$1$ S$2$ S$3$ S$4$

Add protein Station $2$

Add beans

Sour cream and cheese Station $3$

Veggies Efficiency

Pack Station $4$

Checkout

Improved cycle time

Capacity burritos$/$hr