Curve Fit A Fit Type Automatic Manual 0.8 Create Calculated Column O Position (m) 0.6 0.4 Weight Column ---- C 0.2 Coefficients 0 2 3 4 5 Time (s) A*T^2 + BT + C General Equation A -0.08241 A A*T^2+BT+C Quadratic B 0.4475 A O A+BT+C*T^2+D*T^3 Cubic O A+BT+C*T^2+D*T^3+E*T^4 Quartic C 0.1999 A O A+BT+C*T^2+D*T^3+E*T^4+F*T^5 Quintic A*TAB Power A*Tan Variable Power Time Offset Define Function Delete Function Correlation: 0.998905 Status: RMSE: 0.00671685 ? Try Fit Cancel OK0.8 Position (m) 0.6 0.4 0.2 0 2 3 4 5 Time (s)4. The position-time graph of an object that is constantly accelerating should appear parabolic. Use the Curve Fit function of your data using LoggerPro. Select only the parabolic area of the x-t graph where the cart was moving freely. Go to Analyze and select quadratic from the list of equations and then Try fit. Note the values of the 1:1; and C parameters in the quadratic equation. What do these values correspond to? Explain the meaning of these coefficients in terms of equation of motion ((l/ZQLtZHmt- X0 = 0) that you learned in theory class. Do only for Run 1. Answer: The quadratic equation from the graph is P: A*T"2+BT+C P=-0.07888 T2+ 0.5278T-0.03594