Question: d 2 y d x 2 = s e c 2 x , y ( 0 ) = 0 , and , y ' (

d2ydx2=sec2x,y(0)=0, and ,y'(0)=1 Solve for the initial value
d 2 y d x 2 = s e c 2 x , y ( 0 ) = 0 , and , y '

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