$\frac{d^{2}y(t)}{d{t}^2}4y(t)=t,$;$,y(0)=1,\frac{d^{2}y(t)}{d{t}^2}4y(t)=t,$;$,y(0)=1,$

Find the laplace transformation$\frac{d^{2}y(t)}{d{t}^2}4y(t)=t,$;$,y(0)=1,\frac{d^{2}y(t)}{d{t}^2}4y(t)=t,$;$,y(0)=1,$

$\frac{d^{2}y(t)}{d{t}^2}+4y(t)=t,$;$,y(0)=1,$&$,y^{\text{'}}(0)=2$